3.9.66 \(\int \frac {(c x^2)^{3/2}}{x^5 (a+b x)} \, dx\) [866]

Optimal. Leaf size=64 \[ -\frac {c \sqrt {c x^2}}{a x^2}-\frac {b c \sqrt {c x^2} \log (x)}{a^2 x}+\frac {b c \sqrt {c x^2} \log (a+b x)}{a^2 x} \]

[Out]

-c*(c*x^2)^(1/2)/a/x^2-b*c*ln(x)*(c*x^2)^(1/2)/a^2/x+b*c*ln(b*x+a)*(c*x^2)^(1/2)/a^2/x

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Rubi [A]
time = 0.01, antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {15, 46} \begin {gather*} -\frac {b c \sqrt {c x^2} \log (x)}{a^2 x}+\frac {b c \sqrt {c x^2} \log (a+b x)}{a^2 x}-\frac {c \sqrt {c x^2}}{a x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(c*x^2)^(3/2)/(x^5*(a + b*x)),x]

[Out]

-((c*Sqrt[c*x^2])/(a*x^2)) - (b*c*Sqrt[c*x^2]*Log[x])/(a^2*x) + (b*c*Sqrt[c*x^2]*Log[a + b*x])/(a^2*x)

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 46

Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x
)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && Lt
Q[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {\left (c x^2\right )^{3/2}}{x^5 (a+b x)} \, dx &=\frac {\left (c \sqrt {c x^2}\right ) \int \frac {1}{x^2 (a+b x)} \, dx}{x}\\ &=\frac {\left (c \sqrt {c x^2}\right ) \int \left (\frac {1}{a x^2}-\frac {b}{a^2 x}+\frac {b^2}{a^2 (a+b x)}\right ) \, dx}{x}\\ &=-\frac {c \sqrt {c x^2}}{a x^2}-\frac {b c \sqrt {c x^2} \log (x)}{a^2 x}+\frac {b c \sqrt {c x^2} \log (a+b x)}{a^2 x}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 34, normalized size = 0.53 \begin {gather*} -\frac {c^2 (a+b x \log (x)-b x \log (a+b x))}{a^2 \sqrt {c x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(c*x^2)^(3/2)/(x^5*(a + b*x)),x]

[Out]

-((c^2*(a + b*x*Log[x] - b*x*Log[a + b*x]))/(a^2*Sqrt[c*x^2]))

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Mathics [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {cought exception: maximum recursion depth exceeded while calling a Python object} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[(c*x^2)^(3/2)/(x^5*(a + b*x)),x]')

[Out]

cought exception: maximum recursion depth exceeded while calling a Python object

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Maple [A]
time = 0.11, size = 33, normalized size = 0.52

method	result	size
default	\(-\frac {\left (c \,x^{2}\right )^{\frac {3}{2}} \left (b x \ln \left (x \right )-b \ln \left (b x +a \right ) x +a \right )}{a^{2} x^{4}}\)	\(33\)
risch	\(-\frac {c \sqrt {c \,x^{2}}}{a \,x^{2}}+\frac {c \sqrt {c \,x^{2}}\, b \ln \left (-b x -a \right )}{x \,a^{2}}-\frac {b c \ln \left (x \right ) \sqrt {c \,x^{2}}}{a^{2} x}\)	\(62\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2)^(3/2)/x^5/(b*x+a),x,method=_RETURNVERBOSE)

[Out]

-(c*x^2)^(3/2)*(b*x*ln(x)-b*ln(b*x+a)*x+a)/a^2/x^4

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Maxima [A]
time = 0.27, size = 37, normalized size = 0.58 \begin {gather*} \frac {b c^{\frac {3}{2}} \log \left (b x + a\right )}{a^{2}} - \frac {b c^{\frac {3}{2}} \log \left (x\right )}{a^{2}} - \frac {c^{\frac {3}{2}}}{a x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^5/(b*x+a),x, algorithm="maxima")

[Out]

b*c^(3/2)*log(b*x + a)/a^2 - b*c^(3/2)*log(x)/a^2 - c^(3/2)/(a*x)

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Fricas [A]
time = 0.29, size = 33, normalized size = 0.52 \begin {gather*} \frac {{\left (b c x \log \left (\frac {b x + a}{x}\right ) - a c\right )} \sqrt {c x^{2}}}{a^{2} x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^5/(b*x+a),x, algorithm="fricas")

[Out]

(b*c*x*log((b*x + a)/x) - a*c)*sqrt(c*x^2)/(a^2*x^2)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (c x^{2}\right )^{\frac {3}{2}}}{x^{5} \left (a + b x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2)**(3/2)/x**5/(b*x+a),x)

[Out]

Integral((c*x**2)**(3/2)/(x**5*(a + b*x)), x)

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Giac [F] N/A
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Limit: Max order reached or unable to make series expansion Error: Bad Argument Value} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2)^(3/2)/x^5/(b*x+a),x)

[Out]

Limit: Max order reached or unable to make series expansion Error: Bad Argument Value

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {{\left (c\,x^2\right )}^{3/2}}{x^5\,\left (a+b\,x\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2)^(3/2)/(x^5*(a + b*x)),x)

[Out]

int((c*x^2)^(3/2)/(x^5*(a + b*x)), x)

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